I have my own ssh server (on raspberry pi 5, Ubuntu Server 23) but when I try to connect from my PC using key authentication (having password disabled), I get a blank screen. A blinking cursor.

However, once I enter the command eval "$(ssh-agent -s)" and try ssh again, I successfully login after entering my passphrase. I don’t want to issue this command every time. Is that possible?

This does not occur when I have password enabled on the ssh server. Also, ideally, I want to enter my passphrase EVERYTIME I connect to my server, so ideally I don’t want it to be stored in cache or something. I want the passphrase to be a lil’ password so that other people can’t accidentally connect to my server when they use my PC.

46 points

The whole point of ssh-agent is to remember your passphrase. If you don’t want to do that your problem might be that for some reason ssh client doesn’t pick up your key. Try defining it for the host

Also, there’s -v flag for ssh. Use it to debug what’s going on when it doesn’t try to use your key

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7 points
*

okay I tried that, using -i to specify private key. I get the same thing: blank / blinking cursor. When I use verbose -v flag, I see that in all cases (using -i, the config file, and originally) it ends with these two lines (after about 50 lines) :

debug1: Offering public key: /home/username/.ssh/id_rsa RSA SHA256:j3MUkYzhTrjC6PHkIbre3O(etc) agent
debug1: Server accepts key: /home/username/.ssh/id_rsa RSA SHA256:j3MUkYzhTrjC6PHkIbre3OT(etc) agent

where (etc) is some redacted text. It seems the server is ACCEPTING the key, which is nice. But then it’s still a blinking cursor…

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2 points

It seems the server is ACCEPTING the key

Check if it is true. In the server logs.

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4 points
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I’m not sure which logs I can and should check, but when I listen to this: sudo tail -f /var/log/auth.log

I only get this right after I ctrl+C on my blank / blinking cursor screen. (Did this 3 times in a row.)

2024-08-14T11:35:32.874228+02:00 pidoos sshd[3957]: Connection closed by authenticating user pi MY_PUBLIC_IP port 52242 [preauth]
2024-08-14T11:35:50.168160+02:00 pidoos sshd[3975]: Connection closed by authenticating user pi MY_PUBLIC_IP port 39266 [preauth]
2024-08-14T11:35:55.236347+02:00 pidoos sshd[3987]: Connection closed by authenticating user pi MY_PUBLIC_IP port 41318 [preauth]

Where MY_PUBLIC_IP is redacted. I’m not even sure why my public IP is showing. I connect locally. But ports are forwarded, yes.

Using sudo journalctl -u sshd -f does not seem to output anything…

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6 points

The whole point of ssh-agent is to remember your passphrase.

replace passphrase with private key and you’re very correct.

passphrases used to login to servers using PasswordAuthentication are not stored in the agent. i might be wrong with technical details on how the private key is actually stored in RAM by the agent, but in the context of ssh passphrases that could be directly used for login to servers, saying the agent stores passphrases is at least a bit misleading.

what you want is:

  • use Key authentication, not passwords
  • disable passwordauthentication on the server when you have setup and secured (some sort of backup) ssh access with keys instead of passwords.
  • if you always want to provide a short password for login, then don’t use an agent, i.e. unset that environment variable and check ssh_config
  • give your private key a password that fits your needs (average time it shoulf take attackers to guess that password vs your time you need overall to exchange the pubkey on all your servers)
  • change the privatekey every time immediately after someone might have had access to the password protected privkey file
  • do not give others access to your account on your pc to not have to change your private key too often.

also an idea:

  • use a token that stores the private key AND is PIN protected as in it would lock itself upon a few tries with a wrong pin. this way the “password” needed to enter for logins can be minimal while at the same time protecting the private key from beeing copied. but even then one should not let others have access to the same machine (of course not as root) or account (as user, but better not at all) as an unlocked token could also possibly be used to place a second attacker provided key on the server you wanted to protect.

all depends on the level of security you want to achieve. additional TOTP could improve security too (but beware that some authenticator providers might have “sharing” features which could compromise the TOTP token even before its first use.

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5 points

FWIW, I’ve found that the -v flag often doesn’t say why it’s not using your key, just that it isn’t using your key and it has fallen back to password authentication.

It’s usually not terribly helpful for figuring out why it’s not using your key, just that it’s not using your key, which you kind of already know if it’s prompting you for a password. lol

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2 points

Because it’s basically axiomatic: ssh uses all keys it knows about. The system can’t tell you why it’s not using something it doesn’t know it should be able to use. You can give a -i for the certificate to check if it doesn’t know it because the content is broken or the location.

That said: this doesn’t make -v more useful for cases like this, just because there’s a reason!

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2 points

Not OP but everytime I used the verbose output of ssh it didn’t help me one bit. Even adding outrageous verbosity I was still quite confused on what step failed and which didn’t.

I’m probably just bad at understanding SSH but i don’t know it seems like ssh workflow includes many trial and error until it finds a way to connect.

Imo the verbose output of SSH is often not very helpful if you don’t know very well ssh in the first place. Obviously it is still worth a shot and a good advice but don’t expect ssh to clearly state what is going on :)

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1 point

Well, you have configuration and flag options to define what is it supposed to be trying to use. What order, I think too. But definitely understanding SSH a little bit will make the log more understandable. As with everything tbh :D

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3 points

This likely isn’t helpful but it isn’t meant to be a shitpost. However, I will point out this literature:

SSH, The Secure Shell: The Definitive Guide, 2nd Edition

https://github.com/manish-old/ebooks-2/blob/master/O’Reilly - SSH The Secure Shell The Definitive Guide-2.pdf

Other commenters clearly know more than me about tbs ssh, so I’ll otherwise remain silent.

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22 points

Maybe ssh can’t find the key automatically. What is the path to your private key?

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4 points

I’m pretty sure I generated it to ~/.ssh/id_rsa which I think the default location. It is also the location shown in the terminal image in my post.

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2 points

I think some distros disable using RSA by default. Might need to use it explicitly.

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13 points

As mentioned, -v (or -vv) helps to analyze the situation.

My theory is that you already have something providing ssh agent service, but that process is somehow stuck, and when ssh tries to connect it, it doesn’t respond to the connect, or it accepts the connection but doesn’t actually interact with ssh. Quite possibly ssh doesn’t have a timeout for interacting with ssh-agent.

Using eval $(ssh-agent -s) starts a new ssh agent and replaces the environment variables in question with the new ones, therefore avoiding the use of the stuck process.

If this is the actual problem here, then before running the eval, echo $SSH_AUTH_SOCK would show the path of the existing ssh agent socket. If this is the case, then you can use lsof $SSH_AUTH_SOCK to see what that process is. Quite possibly it’s provided by gnome-keyring-daemon if you’re running Gnome. As to why that process would not be working I don’t have ideas.

Another way to analyze the problem is strace -o logfile -f ssh .. and then check out what is at the end of the logfile. If the theory applies, then it would likely be a connect call for the ssh-agent.

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6 points
which ssh 
which ssh-agent
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4 points

I guess it’s worth checking if those names point to the expected binaries, but I also think it would be highly unlikely they would be anything else than just /usr/bin/ssh and /usr/bin/ssh-agent.

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3 points

My theory is that you already have something providing ssh agent service

in the past some xserver environments started an ssh-agent for you just in case of, and for some reason i don’t remember that was annoying and i disabled it to start my agent in my shell environment as i wanted it.

also a possibility is tharlt there are other agents like the gpg-agent that afaik also handles ssh keys.

but i would also look into $HOME/.ssh/config if there was something configured that matches the hostname, ip, or with wildcards* parts of it, that could interfere with key selection as the .ssh/id_rsa key should IMHO always be tried if key auth is possible and no (matching) key is known to the ssh process, that is unless there already is something configured…

not sure if a system-wide /etc/ssh/ssh_config would interfere there too, maybe have a look there too. as this behaviour seems a bit unexpected if not configured specially to do so.

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1 point

I am not sure I “solved” this but when I add this to my startup script for my terminal (~/.zshrc):

SSH_AUTH_SOCK=/tmp/ssh-agent-$USER-socket
export SSH_AUTH_SOCK

it works then. I am not sure I’m still using the ssh agent, but at least it also does not cache my passphrase.

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1 point

you should definitely know what type of authentication you use (my opinion) !! the agent can hold the key forever, so if you are just not asked again when connecting once more, thats what the agent is for. however its only in ram, so stopping the process or rebooting ends that of course. if you didn’t reboot meanwhile maybe try unload all keys from it (ssh-add -D, ssh-add -L) and see what the next login is like.

btw: i use ControlMaster /ControlPath (with timeouts) to even reduce the number of passwordless logins and speed things up when running scripts or things like ansible, monitoring via ssh etc. then everything goes through the already open channel and no authentication is needed for the second thing any more, it gets really fast then.

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2 points
*

I didn’t really follow the former part, but I can give you this:

strace -o logfile -f ssh -p 8322 pi@192.168.2.223 of when I get blank

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6 points

Please don’t ignore the advice about SSH_AGENT_SOCK. It’ll tell yoy what’s going on (but not why).

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2 points

At the end of the log you find:

822413 connect(4, {sa_family=AF_UNIX, sun_path="/run/user/1000/gcr/ssh"}, 110) = 0
...
822413 read(4, 

meaning it’s trying to interact with the ssh-agent, but it (finally) doesn’t give a response.

Use the lsof command to figure out which program is providing the agent service and try to resolve issue that way. If it’s not the OpenSSH ssh-agent, then maybe you can disable its ssh-agent functionality and use real ssh-agent in its place…

My wild guess is that the program might be trying to interactively verify the use of the key from you, but it is not succeeding in doing that for some reason.

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1 point
*

I am not sure I “solved” this but when I add this to my startup script for my terminal (~/.zshrc):

SSH_AUTH_SOCK=/tmp/ssh-agent-$USER-socket
export SSH_AUTH_SOCK

it works then. I am not sure I’m still using the ssh agent, but at least it also does not cache my passphrase/private key

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7 points

Without the ssh-agent invocation:

  • what does ssh-add -L show?
  • what is the original SSH_AUTH_SOCK value?
  • what is listening to that? (Use lsof)

This kind of stuff often happens because there’s a ton of terrible advice online about managing ssh-agent - make sure there’s none if that baked into your shellrc.

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4 points
*
ssh-add -L
ssh-rsa AAAAB3NzaC1yc2EAAAADAQABAAACAQCqS5l(redacted)f0phb8x+fUV1w== username@computername
echo $SSH_AUTH_SOCK
/run/user/1000/gcr/ssh
lsof $SSH_AUTH_SOCK
COMMAND      PID    USER FD   TYPE             DEVICE SIZE/OFF    NODE NAME
gcr-ssh-a 778406 username  3u  unix 0x000000007e25ee6b      0t0   30290 /run/user/1000/gcr/ssh type=STREAM (LISTEN)
gcr-ssh-a 778406 username  6u  unix 0x0000000020f5b559      0t0 2096642 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 12u  unix 0x00000000a6756d60      0t0 2100347 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 15u  unix 0x00000000625cb05a      0t0 2261237 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 21u  unix 0x00000000d0b214f9      0t0 2261238 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 23u  unix 0x00000000a2f197fe      0t0 2349665 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 27u  unix 0x00000000da22a130      0t0 2349668 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 29u  unix 0x000000004f7a1723      0t0 2365382 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 33u  unix 0x00000000e26976b3      0t0 2365389 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 35u  unix 0x00000000b8185a8a      0t0 2375648 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 39u  unix 0x00000000ba41030c      0t0 2375649 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 41u  unix 0x000000006867cb01      0t0 2380999 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 45u  unix 0x0000000091384b95      0t0 2381008 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 47u  unix 0x00000000d5b28b08      0t0 3729149 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)
gcr-ssh-a 778406 username 51u  unix 0x00000000f65088aa      0t0 3731006 /run/user/1000/gcr/ssh type=STREAM (CONNECTED)

All before issuing the ssh-agent

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4 points

It’s the gnome key ring ssh agent.

It’s possible that this has popped up a window asking gor permission / a passphrase / something and you’re not seeing that.

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1 point

Okay, that agent process is running but it looks wedged: multiple connections to the socket seem to be opened, probably your other attempts to use ssh.

The ssh-add output looks like it’s responding a bit, however.

I’d use your package manager to work out what owns it and go looking for open bugs in the tool.

(Getting a trace of that process itself would be handy, while you’re trying again. There may be a clue in its behaviour.)

The server reaponse seems like the handshake process is close to completing. It’s not immediately clear what’s up there I’m afraid.

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1 point

Is this problem a recurring one after a reboot?

If it is it warrants more effort.

If not and you’re happy with rhe lack of closure, you can potentially fix this: kill the old agent (watch out to see if it respawns; if it does and that works, fine). If it doesn’t, you can (a) remove the socket file (b) launch ssh-agent with the righr flag (-a $SSH_AGENT_SOCK iirc) to listen at the same place, then future terminal sessions that inherit the env var will still look in the right place. Unsatisfactory but it’ll get you going again.

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1 point

Search for /run/user/1000/gcr/ssh on the Internet. I’m on my phone and didn’t find the solution, but I’m sure you’ll find it.

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3 points

I searched. When I change this variable (path), it works. So in the startup script for my terminal (~/.zshrc) I added this:

SSH_AUTH_SOCK=/tmp/ssh-agent-$USER-socket
export SSH_AUTH_SOCK

Now it works, but I’m not sure why. Anything BUT /run/user/1000/gcr/ssh works I think

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5 points

please, it’s eval "$(ssh-agent -s)" (quotes!)

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1 point
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well seems to work without tho

edit: made no difference, but I changed it in the post title.

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6 points

Just because it works, doesn’t mean it’s right.

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3 points

I had a similar construct in my bashrc and forgot the quotes. It didn’t throw an error but also didn’t work. Took quite a while to find the issue. So personally, I would recommend trying to quote correctly whenever possible.

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1 point
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I was unclear: I did not mean to imply that it will work with it.

It’s OT, but I’ll clarify since it might be useful for people who find Bash cryptic.

Thing is, roughly speaking:

  • eval will evaluate its first argument as Bash code
  • eval "$(any_command really)" will run run any_command really, take its output and then use it as first argument for eval. So the assumption is that any_command really must output a valid Bash code snippet.

So what eval "$(ssh-agent -s)" really means is, "run ssh-agent -s, collect the output and run it right here, where we are calling eval. Compare to ssh-agent -s | bash – this would also run ssh-agent output but it would run it in a new process–a child process of the current process—so the whatever the snippet would be, it would have no way of affecting state of the parent program, which is why it’s safer.

Aside: The reason we need eval in this case is that we actually need to affect state of the program: that’s the whole point. We need to set several environment variables to values that ssh-agent “knows”. Without eval we would have to “ask” ssh-agent separately for each value (I’m assuming it’s not even supported) and then set all these envvars using eg. export keyword. Using eval we let ssh-agent dictate the whole process: which variables are going to be set to what values, with the caveat that if compromised, it could do “evil” stuff like setting PATH to override common commands with compromised code. etc.

So what’s the problem with the quotes? The Shell syntax, foo "$(bar baz)" will make sure that the thing between quotes is

  • kept verbatim
  • treated as a single argument, even if it contains newlines (with some ugly exceptions to this regarding the final newline)

Now without quotes, Bash (as well as POSIX shell) actually have several things they can do with the output (read man bash for full list, but keep it for a long rainy evening). Some of it involves substituting eg. values like * with matching filenames, some of it may involve actually splitting the output to separate arguments based on spaces or other special characters (which can even be different characters depending on current state, see IFS and the likes).

You can see the difference, if you run eg. printf '[%s]\n' instead of eval. This printf syntax will simply print all of following arguments on a separate line, adding braces before and after. You can compare

printf '|%s|\n' $(ssh-agent -s)      # printf will probably receive multiple extra arguments
printf '|%s|\n' "$(ssh-agent -s)"    # printf will receive just one extra argument (and print it as specified)

(both of these commands should be safe as long as ssh-agent is not compromised and as long I have not made any terrible typo)

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