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How grep with -e (regex) `/log/messages` ? [ solved ]

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Gordon_F@lemmy.ml
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linux@lemmy.ml
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Hi,

I would like to display the new lines of /var/log/messages that contain either IN_MyText or OUT_MyText (no matter where in the line)

I’ve tried

tail -fn 3 /var/log/messages | grep --color --line-buffered -e "(IN|OUT)_MyText"

But the output stay blank, when it should not…

Any ideas ?

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thingsiplay@beehaw.org
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grep by default uses Basic Regular Expressions. This means the ( and ) lose their special meaning and are matched literally. Either use a backslash version \( to have a group, or use Extended Regular Expressions with -E "(IN|OUT)" . In man grep under REGULAR EXPRESSIONS are some differences noted.

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Gordon_F@lemmy.mlOP
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Thank you ! @thingsiplay@beehaw.org 👍
-E solved it :)

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