Day 18: Ram Run

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FAQ

1 point

C#

I did flood fill because i normally just do Dijkstra for this kind of stuff. watching the map print as it flooded was cool, had to disable it for part two though as it was too slow. Just let it run while I made a cup of tea instead of doing a binary search.

spoiler

namespace AoC2024.Day_18;

public class Day18 {

public const string CLEAR = ".";
public const string BLOCKED = "#";
public const string TRAVELED = "O";

public void Go()
{
    var testGrid = GenerateGrid(71, 71);
    PrintGrid(testGrid);
    var coords = GetInputCoordinates(File.ReadAllText("\\AdventOfCode2024\\AoC\\src\\Day_18\\input.txt"));
    
    testGrid = ApplyCoords(testGrid, coords.Take(1024).ToList(), BLOCKED);
    PrintGrid(testGrid);
    FloodFillGrid(testGrid, new Coordinate(0,0), new (70,70));
}

public void GoPart2()
{
    var testGrid = GenerateGrid(71, 71);
    PrintGrid(testGrid);
    var coords = GetInputCoordinates(File.ReadAllText("\\AdventOfCode2024\\AoC\\src\\Day_18\\input.txt"));

    for (int i = 1; i <= coords.Count; i++)
    {
        testGrid = ApplyCoords(testGrid, coords.Take(i).ToList(), BLOCKED);
        PrintGrid(testGrid);
        var result = FloodFillGrid(testGrid, new Coordinate(0,0), new (70,70));
        if (result.Item2 == int.MaxValue)
        {
            var badCoord = coords[i - 1];
            Console.WriteLine($"!!!!Coord Number: {i} with a value of ({badCoord.Column},{badCoord.Row}) IS A BLOCKER!!!!");
            break;
        }
        else if (i%100 == 0)
        {
            var goodCoord = coords[i - 1];
            Console.WriteLine($"Coord Number: {i} with a value of ({goodCoord.Column},{goodCoord.Row}) allows an exit in {result.Item2} steps");
        }
    }
}

public List<List<string>> GenerateGrid(int width, int height)
{
    var grid = new List<List<string>>();
    for (int i = 0; i < height; i++)
    {
        var row = new List<string>();
        for (int j = 0; j < width; j++)
        {
            row.Add(CLEAR);
        }
        grid.Add(row);
    }

    return grid;
}

public void PrintGrid(List<List<string>> grid)
{
    // foreach (var row in grid)
    // {
    //     foreach (var value in row)
    //     {
    //         Console.Write($" {value} ");
    //     }
    //     Console.WriteLine();
    // }
}

public List<List<string>> ApplyCoords(List<List<string>> grid, List<Coordinate> coordinates, string value)
{
    foreach (var coord in coordinates)
    {
        grid[coord.Row][coord.Column] = value;
    }

    return grid;
}

public List<Coordinate> GetInputCoordinates(string input)
{
    var coords = new List<Coordinate>();
    foreach (var pair in input.Split(Environment.NewLine, StringSplitOptions.RemoveEmptyEntries))
    {
        var values = pair.Split(',', StringSplitOptions.RemoveEmptyEntries);
        coords.Add(new Coordinate(values[1], values[0]));
    }

    return coords;
}

public (List<List<string>>, int) FloodFillGrid(List<List<string>> grid, Coordinate start, Coordinate target)
{
    var newGrid = grid.Select(list => new List<string>(list)).ToList();
    var previousGrid = grid;
    newGrid[start.Row][start.Column] = TRAVELED;
    int stepCounter = 0;
    while (newGrid[target.Row][target.Column] != TRAVELED)
    {
        bool valueUpdatedInLoop = false;
        previousGrid = newGrid;
        newGrid = newGrid.Select(list => new List<string>(list)).ToList().ToList();
        
        for (var row = 0; row < grid.Count; row++)
        {
            for (var column = 0; column < grid[row].Count; column++)
            {
                if (previousGrid[row][column] == CLEAR && IsAdjacentEqual(previousGrid, new Coordinate(row,column), TRAVELED))
                {
                    newGrid[row][column] = TRAVELED;
                    valueUpdatedInLoop = true;
                }
            }
        }
        stepCounter++;

        if (!valueUpdatedInLoop)
        {
            return (newGrid,int.MaxValue);
        }
        
        //Console.WriteLine($"Step counter: {stepCounter}");
        PrintGrid(newGrid);
        
    }

    return (newGrid,stepCounter);
}

private bool IsAdjacentEqual(List<List<string>> grid, Coordinate location, string value)
{
    if (location.Row < grid.Count-1 && grid[location.Row+1][location.Column] == value)
    {
        return true;
    }
    
    if (location.Column < grid[0].Count-1 && grid[location.Row][location.Column+1] == value)
    {
        return true;
    }

    if (location.Row > 0 && grid[location.Row-1][location.Column] == value)
    {
        return true;
    }
    
    if (location.Column > 0 && grid[location.Row][location.Column-1] == value)
    {
        return true;
    }

    return false;
}

public struct Coordinate
{
    public Coordinate(int row, int column)
    {
        Row = row;
        Column = column;
    }
    
    public Coordinate(string row, string column)
    {
        Row = int.Parse(row);
        Column = int.Parse(column);
    }
    
    public int Row { get; set; }
    public int Column { get; set; }
}

}

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2 points

C#

using QuickGraph;
using QuickGraph.Algorithms.ShortestPath;

namespace aoc24;

public class Day18 : Solver {
  private int width = 71, height = 71, bytes = 1024;
  private HashSet<(int, int)> fallen_bytes;
  private List<(int, int)> fallen_bytes_in_order;
  private record class Edge((int, int) Source, (int, int) Target) : IEdge<(int, int)>;
  private DelegateVertexAndEdgeListGraph<(int, int), Edge> MakeGraph() => new(GetAllVertices(), GetOutEdges);

  private readonly (int, int)[] directions = [(-1, 0), (0, 1), (1, 0), (0, -1)];

  private bool GetOutEdges((int, int) arg, out IEnumerable<Edge> result_enumerable) {
    List<Edge> result = [];
    foreach (var (dx, dy) in directions) {
      var (nx, ny) = (arg.Item1 + dx, arg.Item2 + dy);
      if (nx < 0 || ny < 0 || nx >= width || ny >= height) continue;
      if (fallen_bytes.Contains((nx, ny))) continue;
      result.Add(new(arg, (nx, ny)));
    }
    result_enumerable = result;
    return true;
  }

  private IEnumerable<(int, int)> GetAllVertices() {
    for (int i = 0; i < width; i++) {
      for (int j = 0; j < height; j++) {
        yield return (i, j);
      }
    }
  }

  public void Presolve(string input) {
    fallen_bytes_in_order = [..input.Trim().Split("\n")
      .Select(line => line.Split(","))
      .Select(pair => (int.Parse(pair[0]), int.Parse(pair[1])))];
    fallen_bytes = [.. fallen_bytes_in_order.Take(bytes)];
  }

  private double Solve() {
    var graph = MakeGraph();
    var search = new AStarShortestPathAlgorithm<(int, int), Edge>(graph, _ => 1, vtx => vtx.Item1 + vtx.Item2);
    search.SetRootVertex((0, 0));
    search.ExamineVertex += vertex => {
      if (vertex.Item1 == width - 1 && vertex.Item2 == width - 1) search.Abort();
    };
    search.Compute();
    return search.Distances[(width - 1, height - 1)];
  }

  public string SolveFirst() => Solve().ToString();

  public string SolveSecond() {
    foreach (var b in fallen_bytes_in_order[bytes..]) {
      fallen_bytes.Add(b);
      if (Solve() > width*height) return $"{b.Item1},{b.Item2}";
    }
    throw new Exception("solution not found");
  }
}
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2 points

Javascript

Reused my logic from Day 16. For part two I manually changed the bytes (i on line 271) to narrow in on a solution faster, but this solution should solve it eventually.

https://blocks.programming.dev/Zikeji/c8fdef54f78c4fb6a79cf1dc5551ff4d

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2 points

Haskell

I did an easy optimization for part 2, but it’s not too slow without.

Solution
import Control.Monad
import Data.Ix
import Data.List
import Data.Map qualified as Map
import Data.Maybe
import Data.Set (Set)
import Data.Set qualified as Set

readInput :: String -> [(Int, Int)]
readInput = map readCoords . lines
  where
    readCoords l = let (a, _ : b) = break (== ',') l in (read a, read b)

findRoute :: (Int, Int) -> Set (Int, Int) -> Maybe [(Int, Int)]
findRoute goal blocked = go Set.empty (Map.singleton (0, 0) [])
  where
    go seen paths
      | Map.null paths = Nothing
      | otherwise =
          (paths Map.!? goal)
            `mplus` let seen' = Set.union seen (Map.keysSet paths)
                        paths' =
                          (`Map.withoutKeys` seen')
                            . foldl' (flip $ uncurry Map.insert) Map.empty
                            . concatMap (\(p, path) -> (,p : path) <$> step p)
                            $ Map.assocs paths
                     in go seen' paths'
    step (x, y) = do
      (dx, dy) <- [(0, -1), (0, 1), (-1, 0), (1, 0)]
      let p' = (x + dx, y + dy)
      guard $ inRange ((0, 0), goal) p'
      guard $ p' `Set.notMember` blocked
      return p'

dropAndFindRoutes goal skip bytes =
  let drops = drop skip $ zip bytes $ drop 1 $ scanl' (flip Set.insert) Set.empty bytes
   in zip (map fst drops) $ scanl' go (findRoute goal (snd $ head drops)) $ tail drops
  where
    go route (p, blocked) = do
      r <- route
      if p `elem` r then findRoute goal blocked else route

main = do
  input <- readInput <$> readFile "input18"
  let routes = dropAndFindRoutes (70, 70) 1024 input
  print $ length <$> (snd . head) routes
  print $ fst <$> find (isNothing . snd) routes
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2 points
*

Dart

I knew keeping my search code from day 16 would come in handy, I just didn’t expect it to be so soon.

For Part 2 it finds that same path (laziness on my part), then does a simple binary chop to home in on the last valid path. (was then searches for the first block that will erm block that path, and re-runs the search after that block has dropped, repeating until blocked. Simple but okay. )

90 lines, half of which is my copied search method. Runs in a couple of seconds which isn’t great, but isn’t bad. Binary chop dropped it to 200ms.

import 'dart:math';
import 'package:collection/collection.dart';
import 'package:more/more.dart';

var d4 = <Point<num>>[Point(0, 1), Point(0, -1), Point(1, 0), Point(-1, 0)];

solve(List<String> lines, int count, Point end, bool inPart1) {
  var blocks = (lines
      .map((e) => e.split(',').map(int.parse).toList())
      .map((p) => Point<num>(p[0], p[1]))).toList();
  var blocksSofar = blocks.take(count).toSet();
  var start = Point(0, 0);
  Map<Point, num> fNext(Point here) => {
        for (var d in d4
            .map((d) => d + here)
            .where((e) =>
                e.x.between(start.x, end.x) &&
                e.y.between(start.y, end.y) &&
                !blocksSofar.contains(e))
            .toList())
          d: 1
      };

  int fHeur(Point here) => 1;
  bool fAtEnd(Point here) => here == end;
  var cost = aStarSearch<Point>(start, fNext, fHeur, fAtEnd);

  if (inPart1) return cost.first;
  var lo = count, hi = blocks.length;
  while (lo <= hi) {
    var mid = (lo + hi) ~/ 2;
    blocksSofar = blocks.take(mid).toSet();
    cost = aStarSearch<Point>(start, fNext, fHeur, fAtEnd);
    (cost.first > 0) ? lo = mid + 1 : hi = mid - 1;
  }
  var p = blocks[lo - 1];
  return '${p.x},${p.y}';
}

part1(lines, count, end) => solve(lines, count, end, true);
part2(lines, count, end) => solve(lines, count, end, false);
That search method
/// Returns cost to destination, plus list of routes to destination.
/// Does Dijkstra/A* search depending on whether heuristic returns 1 or
/// something better.
(num, List<List<T>>) aStarSearch<T>(T start, Map<T, num> Function(T) fNext,
    int Function(T) fHeur, bool Function(T) fAtEnd,
    {multiplePaths = false}) {
  var cameFrom = SetMultimap<T, T>.fromEntries([MapEntry(start, start)]);

  var ends = <T>{};
  var front = PriorityQueue<T>((a, b) => fHeur(a).compareTo(fHeur(b)))
    ..add(start);
  var cost = <T, num>{start: 0};
  while (front.isNotEmpty) {
    var here = front.removeFirst();
    if (fAtEnd(here)) {
      ends.add(here);
      continue;
    }
    var ns = fNext(here);
    for (var n in ns.keys) {
      var nCost = cost[here]! + ns[n]!;
      if (!cost.containsKey(n) || nCost < cost[n]!) {
        cost[n] = nCost;
        front.add(n);
        cameFrom.removeAll(n);
        cameFrom[n].add(here);
      }
      if (multiplePaths && cost[n] == nCost) cameFrom[n].add(here);
    }
  }

  Iterable<List<T>> routes(T h) sync* {
    if (h == start) {
      yield [h];
      return;
    }
    for (var p in cameFrom[h]) {
      yield* routes(p).map((e) => e + [h]);
    }
  }

  if (ends.isEmpty) return (-1, []);
  var minCost = ends.map((e) => cost[e]!).min;
  ends = ends.where((e) => cost[e]! == minCost).toSet();
  return (minCost, ends.fold([], (s, t) => s..addAll(routes(t).toList())));
}
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