If it’s infinite without repeating patterns then it just contain all patterns, no? Eh i guess that’s not how that works, is it? Half of all patterns is still infinity.
No. 1011001110001111… (One 1, one 0, two 1s, two zeros…) Doesn’t contain repeating patterns. It also doesn’t contain any patterns with ‘2’ in it.
But pi is believed to be normal. https://en.m.wikipedia.org/wiki/Normal_number
So it should contain all finite patterns an infinite number of times.
However, as the name implies, this is nothing special about pi. Almost all numbers have this property. If anything, it’s the integers that we should be finding weird, like you mean to tell me that every single digit after the decimal point is a zero? No matter how far you go, just zeroes forever?
Yeah, but your number doesn’t fit pi. It may not have a pattern, but it’s predictable and deterministic.
Pi is predictable and deterministic.
Computer programs exist that can tell you what the next digit is. That means it’s deterministic, and running the program will give you a prediction for each digit (within the memory constraints of your computer).
The fact that it’s deterministic is exactly why pi is interesting. If it was random it would typically be much easier to prove properties about it’s digits.
Not, the example I gave have infinite decimals who doesn’t repeat and don’t contain any patterns.
What people think about when said that pi contain all patters, is in normal numbers. Pi is believed to be normal, but haven’t been proven yet.
An easy example of a number who contains “all patterns” is 0.12345678910111213…