Day 20: Race Condition

Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • You can send code in code blocks by using three backticks, the code, and then three backticks or use something such as https://topaz.github.io/paste/ if you prefer sending it through a URL

FAQ

You are viewing a single thread.
View all comments
2 points

C

Note to self: reread the puzzle after waking up properly! I initially wrote a great solution for the wrong question (pathfinding with a given number of allowed jumps).

For the actual question, a bit boring but flood fill plus some array iteration saved the day again. Find the cost for every open tile with flood fill, then for each position and offset combination, see if that jump yields a lower cost at the destination.

For arbitrary inputs this would require eliminating the non-optimal paths, but the one path covered all open tiles.

Code
#include "common.h"

#define GB 2	/* safety border on X/Y plane */
#define GZ (GB+141+2+GB)

static char G[GZ][GZ];		/* grid */
static int  C[GZ][GZ];		/* costs */
static int sx,sy, ex,ey;	/* start, end pos */

static void
flood(int x, int y)
{
	int lo = INT_MAX;

	if (x<1 || x>=GZ-1 ||
	    y<1 || y>=GZ-1 || G[y][x]!='.')
		return;

	if (C[y-1][x]) lo = MIN(lo, C[y-1][x]+1);
	if (C[y+1][x]) lo = MIN(lo, C[y+1][x]+1);
	if (C[y][x-1]) lo = MIN(lo, C[y][x-1]+1);
	if (C[y][x+1]) lo = MIN(lo, C[y][x+1]+1);

	if (lo != INT_MAX && (!C[y][x] || lo < C[y][x])) {
		C[y][x] = lo;

		flood(x, y-1); flood(x-1, y);
		flood(x, y+1); flood(x+1, y);
	}
}

static int
count_shortcuts(int lim, int min)
{
	int acc=0, x,y, dx,dy;

	for (y=GB; y<GZ-GB; y++)
	for (x=GB; x<GZ-GB; x++)
	for (dy = -lim; dy <= lim; dy++)
	for (dx = abs(dy)-lim; dx <= lim-abs(dy); dx++)
		acc += x+dx >= 0 && x+dx < GZ &&
		       y+dy >= 0 && y+dy < GZ && C[y][x] &&
		       C[y][x]+abs(dx)+abs(dy) <= C[y+dy][x+dx]-min;

	return acc;
}

int
main(int argc, char **argv)
{
	int x,y;

	if (argc > 1)
		DISCARD(freopen(argv[1], "r", stdin));
	for (y=2; fgets(G[y]+GB, GZ-GB*2, stdin); y++)
		assert(y < GZ-3);

	for (y=GB; y<GZ-GB; y++)
	for (x=GB; x<GZ-GB; x++)
		if (G[y][x] == 'S') { G[y][x]='.'; sx=x; sy=y; } else
		if (G[y][x] == 'E') { G[y][x]='.'; ex=x; ey=y; }

	C[sy][sx] = 1;

	flood(sx, sy-1); flood(sx-1, sy);
	flood(sx, sy+1); flood(sx+1, sy);

	printf("20: %d %d\n",
	    count_shortcuts(2, 100),
	    count_shortcuts(20, 100));

	return 0;
}

https://codeberg.org/sjmulder/aoc/src/branch/master/2024/c/day20.c

permalink
report
reply

Advent Of Code

!advent_of_code@programming.dev

Create post

An unofficial home for the advent of code community on programming.dev!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2024

Solution Threads

M T W T F S S
1
2 3 4 5 6 7 8
9 10 11 12 13 14 15
16 17 18 19 20 21 22
23 24 25

Rules/Guidelines

  • Follow the programming.dev instance rules
  • Keep all content related to advent of code in some way
  • If what youre posting relates to a day, put in brackets the year and then day number in front of the post title (e.g. [2024 Day 10])
  • When an event is running, keep solutions in the solution megathread to avoid the community getting spammed with posts

Relevant Communities

Relevant Links

Credits

Icon base by Lorc under CC BY 3.0 with modifications to add a gradient

console.log('Hello World')

Community stats

  • 483

    Monthly active users

  • 108

    Posts

  • 1.1K

    Comments