Day 3: Mull It Over
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I couldn’t figure it out in haskell, so I went with bash for the first part
Shell
cat example | grep -Eo "mul\([[:digit:]]{1,3},[[:digit:]]{1,3}\)" | cut -d "(" -f 2 | tr -d ")" | tr "," "*" | paste -sd+ | bc
but this wouldn’t rock anymore in the second part, so I had to resort to python for it
Python
import sys
f = "\n".join(sys.stdin.readlines())
f = f.replace("don't()", "\ndon't()\n")
f = f.replace("do()", "\ndo()\n")
import re
enabled = True
muls = []
for line in f.split("\n"):
if line == "don't()":
enabled = False
if line == "do()":
enabled = True
if enabled:
for match in re.finditer(r"mul\((\d{1,3}),(\d{1,3})\)", line):
muls.append(int(match.group(1)) * int(match.group(2)))
pass
pass
print(sum(muls))
2 points
1 point