Call the Priest(lemmy.world)

posted 1 year ago

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1 year ago

You basically got it yeah. You can do x % 2 and check if that is 0, as % calculates the remainder (in python at least)

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1 year ago

y = 1

while y ==1:

x = input(“Enter Number”)

if int(x) % 2 == 0:

print(“EVEN”)

else:

print(“ODD”)

I don’t know why, but I opened up my IDLE for the first time in a year and did it.

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1 year ago

int val = 3;
bool is_odd = val & (decltype(val))0x01 == (decltype (val))1;

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